4α - k + 8 = 0
det(Qadj(P)) = 213
α = 0, k = 8
det(Padj(Q)) = 29
AsPQ=kI⇒Q=kPI|P|=⎡⎢⎣3230α0⎤⎥⎦,=(20+12α).. (1)NowQ=k|P|(adjP)I⇒Q=k(20+12α)⎡⎢⎣5α10−α3α0(α)020⎤⎥⎦⎡⎢⎣100010001⎤⎥⎦∵q23=−k8⇒−k(3α+4)(20+12α)=−k8⇒2(3α+4)=5+3α3α=⇒α=Also|Q|=k3|I||P|⇒k22=k3(20+12α)∵from(1)