devarshi-dt-logo

Question:

Light wavelength 550 nm falls normally on a slit of width 22.0 × 10⁻⁶ cm. The angular position of the second minima from the central maximum will be (in radians)

π/6

π/8

π/12

π/4

Solution:

for single slit, the angular position is given by
sinθ = nλ/d
Here, n = 2
sinθ = 2 × 550 × 10⁻⁹ m / (22.0 × 10⁻⁶ m)
sinθ = 1/2
θ = π/6