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Question:

Magnetic field in a plane electromagnetic wave is given by →B=B₀sin(kx+ωt)ĵT. Expression for corresponding electric field will be: Where c is speed of light.

→E=B₀csin(kx+ωt)k̂V/m

→E=B₀csin(kx+ωt)k̂V/m

→E=-B₀csin(kx+ωt)k̂V/m

→E=B₀csin(kx-ωt)k̂V/m

Solution:

→E=c→B
→B=B₀sin(kx+ωt)ĵ
→E=B₀Csin(kx+ωt)k̂V/m