Mixture X = 0.02 mol of [Co(NH3)5SO4]Br and 0.02 mol of [Co(NH3)5Br]SO4 was prepared in 2L of solution. 1L of mixture X + excess AgNO3 → Y 1L of mixture X + excess BaCl2 → Z Number of moles of Y and Z are :

1.0 L of mixture X contain 0.01 mole of each [(Co(NH3)5SO4]Br and [Co(NH3)5Br]SO4. Also, with AgNO3, only [(Co(NH3)5SO4)]Br reacts to give AgBr precipitate as [Co(NH3)5SO4]Br + AgNO3 → [Co(NH3)5SO4]NO3 + AgBr (0.01 mol) 0.01 mol excess. Similarly, in the second reaction, BaSO4 (Z) will be precipitated. Hence option C is correct.