devarshi-dt-logo

Question:

Molar conductives (Λm) at infinite dilution of NaCl, HCl and CH3COONa are 126.4, 425.9 and 91.0 Scm²mol⁻¹ respectively. Λm for CH3COOH will be:

290.8 Scm²mol⁻¹

390.5 Scm²mol⁻¹

180.5 Scm²mol⁻¹

425.5 Scm²mol⁻¹

Solution:

Let x be the molar conductivity of acetic acid.

Λm(CH3COOH) = Λm(CH3COONa) + Λm(HCl) - Λm(NaCl)

x = 91.0 + 425.9 - 126.4
x = 290.5 Scm²mol⁻¹

Therefore, the molar conductivity of CH3COOH at infinite dilution is 290.5 Scm²mol⁻¹.