290.8 Scm²mol⁻¹
390.5 Scm²mol⁻¹
180.5 Scm²mol⁻¹
425.5 Scm²mol⁻¹
Let x be the molar conductivity of acetic acid.
Λm(CH3COOH) = Λm(CH3COONa) + Λm(HCl) - Λm(NaCl)
x = 91.0 + 425.9 - 126.4
x = 290.5 Scm²mol⁻¹
Therefore, the molar conductivity of CH3COOH at infinite dilution is 290.5 Scm²mol⁻¹.