'n' moles of an ideal gas undergoes a process A→B as shown in the figure. The maximum temperature of the gas during the process will be:

We need to write the relation between P and V and maximize the product PV. P = −P0V0/V + 3P0. PV = (−P0V0/V + 3P0)V = −P0V0 + 3P0V. Since nRT = PV, we have nRT = −P0V0 + 3P0V. Differentiating wrt V and putting it equal to 0, we get, V = 3V0/2. Hence, P = 3P0/2. Therefore, T = 9P0V0/4nR