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Question:

On which of the following lines lies the point of intersection of the line x=y=z and the plane x+y+z=2?

x=y=z+33

x=y=z

x+33=4-y3=z+1

x=y=z+4

Solution:

The correct option is x=y=z+4
General point on the given line is
x=λ+4
y=λ+5
z=λ+3
Solving with plane, 2λ+4+2λ+5+λ+3=2
5λ+12=2
5λ=-10
λ=-2
x=2*-2+4=0
y=2*-2+5=1
z=1*-2+3=1
Points will satisfy option C