On which of the following lines lies the point of intersection of the line x=y=z and the plane x+y+z=2?
x=y=z+33
x=y=z
x+33=4-y3=z+1
x=y=z+4
Solution:
The correct option is x=y=z+4 General point on the given line is x=λ+4 y=λ+5 z=λ+3 Solving with plane, 2λ+4+2λ+5+λ+3=2 5λ+12=2 5λ=-10 λ=-2 x=2*-2+4=0 y=2*-2+5=1 z=1*-2+3=1 Points will satisfy option C