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Question:

One circle touches all sides of □ABCD. If AB=5, BC=8, CD=6; then AD=?

3

9

7

4

Solution:

Given that a circle touches all the four sides of □ABCD.
∴AB, BC, CD and AD are chords of the circle
∴AB + CD = AD + BC
∴5 + 6 = AD + 8
∴AD = 3