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Question:

One mole of a compound reacts with one mole of a compound CD according to the equation AB(g) + CD(g) ⇌ AD(g) + CB(g). When equilibrium had been established it was found that 3/4 mole each of reactants AB and CD had converted to AD and CB. There is no change in volume. The equilibrium constant for the reaction is :

615

19

195

9

Solution:

equilibrium constant =?
equilibrium constant k=[AD][CB]/[AB][CD]=Rf/Rb
K= (3/4) × (3/4) / (1/4) × (1/4)
K=9