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Question:

One mole of a monatomic ideal gas goes through a thermodynamic cycle, as shown in the volume versus temperature (V-T) diagram. The correct statement(s) is/are?

Work done in this thermodynamic cycle(1→2→3→4→1is|W|=12RT0

The ratio of heat transfer during processes 1→2 and 2→3 is |Q1→2/Q2→3|=5/3

The above the thermodynamic cycle exhibits only isochoric and adiabatic processes

The ratio of heat transfer during processes 1→2 and 3→4 is |Q1→2/Q2→3|=1/2

Solution:

Correct option is B. The ratio of heat transfer during processes 1→2 and 2→3 is |Q1→2/Q2→3|=5/3
(4)|ΔQ1→2/ΔQ3→4|=|nCpΔT1→2/nCpΔT3→4|=T0/(T0/2)=2
(2)|ΔQ1→2/ΔQ2→3|=|nCpΔT1→2/nCvΔT2→3|=Cp/Cv=5/3
(1)Wcycle=P0V0=nR[T0/2] [Using point no.4]
(3)Wrong as no adiabatic process is involved.
Correct option 1,2.