−60 kJ
20 J
−14 kJ
20 kJ
ΔU=nCvΔT
where n is no. of moles, Cv is heat capacity at constant volume and ΔT is temperature change
for diatomic gas Cv=3/2R
from ideal gas equation T1=P1V1/R and T2=P2V2/R
ΔU=Cv(T2−T1)
ΔU=3/2R(P2V2/R−P1V1/R)
ΔU=3/2(P2V2−P1V1)=−14 kJ
hence correct answer is option C