One of the two digits of a two-digit number is three times the other digit. If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88. What is the original number?

Let the digits at tens place: x and ones place: 3x
∴original number = 10x + 3x = 13x
Interchange the digits, Digits at ones place and tens place will be x and 3x
Numbers: 10 × 3x + x = 30x + x = 31x
As per the questions
Original number + New number = 88
13x + 31x = 88
44x = 88
x = 2
Original number = 13x = 13 × 2 = 26
Or interchanging them, we will get 62