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Let the initial amount with them beRs. xandRs. yrespectively.Then according to the question:x+100=2(y−1;00)x+100=2y−2;00x−2;y=−300…(1)And,6(x−1;0)=(y+10)6x−6;0=y+106x−y=70…(2)Multiplying equation(2)by 2, we get:12x−2;y=140…(3)Subtracting equation(1)from equation(3), we get:11x=140+30011x=440x=40Substitute the vale ofxin equation(1), we get:40−2;y=−30040+300=2y2y=340y=3402=170∴The friends hadRs. 40andRs. 170with them respectively.