Parallelogram ABCD and rectangle ABEF are on the same base AB and have equal areas. Show that the perimeter of the parallelogram is greater than that of the rectangle.

Given: ParallelogramABCDand rectangleABEFare on same base and have equal areas.AB=CD...opposite side of parallelogramAB=EF...opposite side of rectangleand,∠F=∠E=90∘AD>AFandBC>BE(Hypotenuse of right angle is greater than other sides )Now,Perimeter of□ABCD=AB+BC+CD+DAPerimeter of□ABEF=AB+BE+EF+FASince,CD=EFandAD>AF,BC>BE∴Perimeter of parallelogramABCD>Perimeter of rectangleABEF