Eduprobe
Question:
pH of a 0.01M solution (Ka=6.6×10⁻⁴) is:
7.6
2.6
8
5
Solution:
α=√KaC=√6.6×10⁻⁴×0.01=√6.6×10⁻⁶=0.257
[H+]=Cα=0.01×0.257=2.57×10⁻³
pH=3-log2.5=2.60
7.6
2.6
8
5
α=√KaC=√6.6×10⁻⁴×0.01=√6.6×10⁻⁶=0.257
[H+]=Cα=0.01×0.257=2.57×10⁻³
pH=3-log2.5=2.60