Point C is the midpoint of line segment AB, prove that every line segment has one and only one midpoint.
Solution:
AC=BC.. (i) If possible, let D be another mid-point of AB. AD=DB.. (ii) Subtracting (ii) from (i) AC–AD=BC–DB DC = −DC ( ∵ AC−AD=DC and CB−DB=−DC) DC+DC=0 2DC=0 DC=0 So, C and D coincide. Thus, every line segment has one and only one mid-point.