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Question:

Point P is in the exterior of the circle. A tangent is drawn from point P that touches the circle at T. If PT=8, then OP is:

13

17

23

7

Solution:

Pis in the exterior of⊙(0.15).For△PTO,m∠OTP=90oOP2=OT2+PT2... [By Pythagoras theorem]⟹OP2=(15)2+(8)2=289∴OP=17