Predict the products of the following reactions:
(i) CH3-C=O + N2N-NH3 →
(ii) KOH/Glycol, Δ
(ii) C6H5-CO-CH3 + NaOH/I2 →
(iii) CH3COONa + NaOH/CaO → Δ

(i) The reaction of acetaldehyde (CH3CHO) with hydrazine (N2H4) in the presence of a base like KOH forms a hydrazone. The reaction is as follows:
CH3CHO + H2NNH2 → CH3CH=NNH2 + H2O

(ii) This reaction is a haloform reaction. Acetophenone (C6H5COCH3) reacts with iodine (I2) in the presence of a base (NaOH) to form iodoform (CHI3) and sodium benzoate (C6H5COONa).

C6H5COCH3 + 3I2 + 4NaOH → CHI3 + C6H5COONa + 3NaI + 3H2O

(iii) This is a decarboxylation reaction. Sodium acetate (CH3COONa) undergoes decarboxylation upon heating with sodium hydroxide (NaOH) and calcium oxide (CaO). This results in the formation of methane (CH4) and sodium carbonate (Na2CO3).

CH3COONa + NaOH → CH4 + Na2CO3