Given,ABCDis a cyclic parallelogram.To prove,ABCDis a rectangle.Proof:∠1+∠2=180°...Opposite angles of a cyclic parallelogramAlso, Opposite angles of a cyclic parallelogram are equal.Thus,∠1=∠2⇒∠1+∠1=180°⇒∠1=90°One of the interior angle of the parallelogram is right angled. Thus,ABCDis a rectangle.