Eduprobe
Question:
Prove that: 2sin²(3π/4) + 2cos²(π/4) + 2sec²(π/3) = 10
Solution:
LHS = 2sin²(3π/4) + 2cos²(π/4) + 2sec²(π/3)
= 2sin²(π - π/4) + 2(1/√2)² + 2(2)²
= 2(1/√2)² + 1 + 8
= 1 + 1 + 8
= 10
= RHS
LHS = 2sin²(3π/4) + 2cos²(π/4) + 2sec²(π/3)
= 2sin²(π - π/4) + 2(1/√2)² + 2(2)²
= 2(1/√2)² + 1 + 8
= 1 + 1 + 8
= 10
= RHS