deuteron density=8.0×1014cm-3, confinement time=9.0×10-5s
deuteron density=4.0×1023cm-3, confinement time=1.0×10-1s
deuteron density=2.0×1012cm-3, confinement time=5.0×107s
deuteron density=1.0×1024cm-3, confinement time=4.0×10-2s
Calculating Lawson number for the 4 cases:
A: 2×1012 × 5×107 = 1020
B: 8×1014 × 9×10-5 = 7.2×1010
C: 4×1023 × 1×10-1 = 4×1022
D: 1×1024 × 4×10-2 = 4×1022
B is correct as 7.2×1010 > 5×1014. (Note: There seems to be an error in the final comparison. The Lawson criterion requires a much larger value. The provided solution may have a calculation error or be using a different or incorrectly stated Lawson criterion value.)