devarshi-dt-logo

Question:

Same spring is attached with 2 kg, 3 kg and 1 kg blocks in three different cases as shown in figure. If x1, x2, x3 be the extensions in the spring in the three cases, then

x1=0,x3>x2

x1>x2>x3

x2>x1>x3

x3>x2>x1

Solution:

If T1, T2, T3 are the tensions in the strings in the three cases, we have

Case 1: T1 = 2g
x1 = T1/k = 2g/k

Case 2: T2 = 3g
x2 = T2/k = 3g/k

Case 3: T3 = 1g
x3 = T3/k = g/k

Therefore, x2 > x1 > x3