Show how you would connect 3 resistors, each of resistance 6 ohm, so that the combination has a resistance of (i) 9 ohm (ii) 4 ohm

We are given 3 resistors each of resistance 6 Ω. Equivalent resistance of resistors in series is more than the individual resistance of each resistor while equivalent resistance of resistance in parallel is less than the individual resistance of each resistor
(i)To get an equivalent resistance of 9 Ω, at least one six ohm resistor should be connected in series with the other resistors. Since, Req=R1+R2
9=6+R2
R2=3 Ω ⇒ R2<6 Ω
Connecting the remaining two resistors in parallel will yield an equivalent resistance of 3 Ω. Hence, the first figure shows the configuration of resistors to get equivalent resistor of 9 Ω
(ii)To get an equivalent resistance of 4 Ω, no six ohm resistor should be connected in series with the other resistors. Let one of the branches have only one 6 Ω resistor. Since,
1/Req = 1/R1 + 1/R2
1/4 = 1/6 + 1/R2
R2 = 12 Ω
Connecting the remaining two resistors in series will yield an equivalent resistance of 12 Ω. Hence, the second figure shows the configuration of resistors to get equivalent resistor of 4 Ω.