Solve for x: 4x² - 4ax + (a² - b²) = 0

The given quadratic equation is 4x² - 4ax + (a² - b²) = 0
We have 4x² - 4ax + (a+b)(a - b) = 0
→ 4x² + [-2a - 2a + 2b - 2b]x + (a - b)(a + b) = 0
[We can write -4a = [-2a - 2a + 2b - 2b]]
→ 4x² + (2b - 2a)x - (2a + 2b)x + (a - b)(a + b) = 0
→ 4x² + 2(b - a)x - 2(a + b)x + (a - b)(a + b) = 0
→ 2x[2x - (a - b)] - (a + b)[2x - (a - b)] = 0
→ [2x - (a - b)][2x - (a + b)] = 0
→ 2x - (a - b) = 0, 2x - (a + b) = 0
→ x = (a - b)/2, (a + b)/2