Solve that following for x: 12a+b+2x=12a+1b+12x

12a+b+2x=12a+1b+12x⇒12x+b+2a−12x=12a+1b+12x−12x⇒2x−2;a−b−2;x2x(2a+b+2x)=b+2a2ab⇒−2;a−b2x(2a+b+2x)=b+2a2ab⇒−1x(2a+b+2x)=1ab⇒2x2+bx+2ax+ab=0⇒x(2x+b)+a(2x+b)=0⇒(2x+b)(x+a)=0If2x+b=0thenx=−b2Andx+a=0thenx=−a