devarshi-dt-logo

Question:

Solve the following equation and check your results: 4z + 3 = 6 + 2z

Solution:

Transpose 2z to LHS and 3 to RHS
4z - 2z = 6 - 3
2z = 3
z = 3/2
LHS → 4z + 3 = 4 × 3/2 + 3 = 9
RHS → 6 + 2z = 6 + 2 × 3/2 → 6 + 3 = 9
LHS = RHS
Hence proved