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Question:

Strong reducing behaviour of H3PO2 is due to:

presence of two -OH groups and one P - H bond

high oxidation state of phosphorus

high electron gain enthalpy of phosphorus

presence of one - OH group and two P - H bonds

Solution:

Strong reducing behavior of H3PO2 is due to the presence of one -OH group and two P-H bonds. The two P-H bonds are responsible for the strong reducing property. The hydrogen atoms attached directly to the phosphorus atom are easily oxidized, losing electrons and leading to the reduction of other species. Therefore, the presence of these P-H bonds is crucial for the strong reducing nature of H3PO2.