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Question:

The acceleration of light pulley is

F/m

F/2m

F/4m

F/8m

Solution:

Let the acceleration of the pulley bea.
From the constraint relation, the acceleration of the block is, thus,2a.
Consider the forces acting on the block,T=m(2a)
Also consider forces acting on the pulley,F=2T
Hence from the two equations,a=T/2m=F/2/2m=F/4m