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Question:

The angle of elevation of a tower from a point 150 m away from the foot of the tower is 60°. Find the height of the tower.

Solution:

The angle of elevation = 60°
Distance from tower = BC = 150 m
Height of tower = AB = h
tan 60° = AB/BC = Height/Distance
tan 60° = h/150
h = √3 × 150
h = 150√3 m