The area (in sq. units) of the region A = (x,y): y²/2 ≤ x ≤ y+4 is

Correct option is B. 18
y²/2 = x; x - y - 4 = 0
(x-4)² = 2x ⇒ x² + 16 - 8x - 2x = 0; x = 0 ⇒ x = 8, 2; y = 4, -2
A = ∫₋₂⁴ (y + 4 - y²/2) dy = |y²/2|₋₂⁴ + |4y|₋₂⁴ + |y³/6|₋₂⁴ = (8 - 2) + 4(6) - 1/6