The area (in sq. units) of the region bounded by the curve x²=4y and the straight line x=4y

x=4y x²=4y
y=x/4 and y=x²/4
Solving the equations, ⇒x²=x+2 ⇒x²-x-2=0 ∴x=2, -1
Area of required region = Area of straight line - area under parabola
So, ∫₋₁² (x+2/4 - x²/4)dx = 98