The area (in square units) of the region bounded by the curves y+2x²=0 and y+3x²=1 is equal to?

Solving both the equations we get point of intersection both the curves as (1,-2) and (-1,-2). Thus required area is given by, A=∫₋₁¹(1-x² - (-2x²))dx = ∫₋₁¹(1+x²)dx = [x + x³/3]₋₁¹ = (1 + 1/3) - (-1 - 1/3) = 4/3 + 4/3 = 8/3. The options provided seem to be incorrect. The correct area is 8/3 square units. There appears to be a calculation error or mismatch between the question and provided options.