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Question:

The circle x² + y² - 8x = 0 and hyperbola x²/9 - y²/4 = 1 intersect at the points A and B. Equation of a common tangent with positive slope to the circle as well as to the hyperbola is

4x - 7y + 4 = 0

2x - √5y + 4 = 0

2x - √5y = 0

3x - 4y + 8 = 0

Solution:

Equation of circle x² + y² - 8x = 0
(x - 4)² + y² = 16
Equation of hyperbola x²/9 - y²/4 = 1.