The circle x² + y² - 8x = 0 and hyperbola x²/9 - y²/4 = 1 intersect at the points A and B. Equation of a common tangent with positive slope to the circle as well as to the hyperbola is
4x - 7y + 4 = 0
2x - √5y + 4 = 0
2x - √5y = 0
3x - 4y + 8 = 0
Solution:
Equation of circle x² + y² - 8x = 0 (x - 4)² + y² = 16 Equation of hyperbola x²/9 - y²/4 = 1.