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Question:

The circuit shown here has two batteries of 8.0 V and 16.0 V and three resistors 3Ω, 9Ω and 9Ω and a capacitor 5.0µF. The current I in the circuit at steady state is:

0.67 A

1.6 A

0.25 A

2.5 A

Solution:

Answer is B

[Detailed explanation of how to arrive at the solution for current I would go here. This would involve circuit analysis techniques like Kirchhoff's laws or nodal analysis, considering the steady state condition (capacitor acts as an open circuit). The specific calculations would depend on the circuit diagram which is missing from the input data.]