The coach of a cricket team buys 3 bats and 6 balls for Rs 3900. Later, she buys another bat and 3 more balls of the same kind for Rs 1300. Represent this situation algebraically.
Solution:
Let the cost of a bat be Rs. x and cost of a ball be Rs. y. Then algebraically representation of the question is - 3x + 6y = 3900 => x + 2y = 1300 and x + 3y = 1300