15
10
14
12
The correct option is B15(1 - t⁶)³(1 - t)⁻³(1 - 3t⁶ + 3t¹²)(1 - t)⁻³→coefficient of t⁴ in (1 - t)⁻³ is ³⁺⁴⁻¹C₄ = ⁶C₂ = 15