The common tangent to the circles x² + y² = 4 and x² + y² + 6x + 8y - 24 = 0 also passes through the point: (-4, 6), (6, -2), (-6, 4), (4, -2)

The correct option is B (6, -2)
Circle touches internally
C1(0,0): r1 = 2
C2: (-3, -4); r2 = 7
C1C2 = |r1 - r2|
S1 - S2 = 0 => equation of common tangent 6x + 8y - 24 = 0
3x + 4y = 10
(6, -2) satisfies the equation.