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Question:

The conductivity of 0.20 M solution of KCl at 298 K is 0.025 S cm⁻¹. Calculate its molar conductivity.

Solution:

Given, K = 0.025 S cm⁻¹ and C = 0.2 M
Formula of molar conductivity, Λm = Λm × 1000/C = 0.025 × 1000/0.2 = 125 S cm² mol⁻¹