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Question:

The correct combination is: [Ni(CN)4]2−-tetrahedral; [Ni(CO)4]-paramagnetic [NiCl4]2−-paramagnetic; [Ni(CO)4]-tetrahedral [NiCl4]2−-diamagnetic; [Ni(CO)4]-square-planar [NiCl4]2−-square-planar; [Ni(CN)4]2−-paramagnetic

[NiCl4]2−-paramagnetic;[Ni(CO)4]-tetrahedral

[NiCl4]2−-square-planar;[Ni(CN)4]2−-paramagnetic

[Ni(CN)4]2−-tetrahedral;[Ni(CO)4]-paramagnetic

[NiCl4]2−-diamagnetic;[Ni(CO)4]-square-planar

Solution:

[Ni(CN)4]2− is square planar, diamagnetic (0 unpaired electrons) with dsp2 hybridization.