Fe>Co>Cr>Ti
Cr=Fe>Co>Ti
Cr>Fe>Co>Ti
Cr=Fe>Ti>Co
Cr=[Ar] 4s1 3d5; 6 unpaired electronsFe=[Ar] 4s2 3d6; 4 unpaired electronsCo=[Ar] 4s2 3d7; 3 unpaired electronsTi=[Ar] 4s2 3d2; 2 unpaired electronsCr>Fe>Co>TiHence, option C is correct.