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Question:

The cylindrical tube of a spray pump has radius R, one end of which has n fine holes, each of radius r. If the speed of the liquid in the tube is V, the speed of the ejection of the liquid through the holes is:

VR2n3r2

V2Rnr

VR2n2r2

VR2nr2

Solution:

Using equation of continuity, Av = constant
A1v1 = A2v2
∴ πR²V = (nπr²)v'
where nπr² is the total area of n fine holes.
⇒v' = VR²/nr²