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Question:

The de-Broglie's wavelength of electron present in the first Bohr orbit of a H atom is?

2π × 0.529 Å

4 × 0.529 Å

0.529 × 2π Å

0.529 Å

Solution:

The correct option is B (2π × 0.529 Å)

First Bohr orbit of 'H' atom has radius r = 0.529 Å
Also, the angular momentum is quantized.
mvr = h/2π
2πr = h/mv
λ = h/mv = 2π × 0.529 Å

The de Broglie's wavelength of electron present in the first Bohr orbit of H atom is 2π × 0.529 Å.
So, the correct option is B