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Question:

The decomposition of dinitrogen pentoxide is described by the chemical equation, 2 N₂O₅(g) → 4 NO₂(g) + O₂(g). If the rate of disappearance of N₂O₅ is equal to 1.80 mol/min at a particular moment, what is the rate of appearance of NO₂ at that moment?

1.6 mol/min

3.6 mol/min

2.6 mol/min

6.6 mol/min

Solution:

Correct option is C. 3.6 mol/min
2N₂O₅→4NO₂+O₂
−d[N₂O₅]/2dt = d[NO₂]/4dt = d[O₂]/dt
Given: −d[N₂O₅]/dt = 1.80 mol/min
−d[N₂O₅]/2dt = d[NO₂]/4dt
d[NO₂]/dt = 2 × 1.8 = 3.6 mol/min
Hence, option C is correct.