The decreasing order of bond angles in BF3, NH3, PF3 and I⁻ is:

lp-lp > lp-bp > bp-bp
Due to lp-lp repulsion in PF3, F-P-F angle will be less than that of BF3 ∴ BF3 < PF3
BF3 > NH3, as the geometry of BF3 is trigonal planar while that of NH3 is tetrahedral
As the Fluorine atom pulls the lone pair of electron on P atom, lp-bp repulsion is more predominant. Thus NH3 > PF3
thus, BF3 > NH3 > PF3
I⁻ ion is linear. This bond angle is 180o. ∴ I⁻ > BF3 > NH3 > PF3