The density of a solution prepared by dissolving 120 g of urea (mol. mass = 60) in 1000 g of water is 1.15 g/mL. The molarity of this solution is:

Total mass of solution = 120 g + 1000 g = 1120 g
moles of urea = 120 g / 60 g/mol = 2 moles
Density = mass / volume = 1.15 g/mL
Volume of solution = mass / density = 1120 g / (1.15 g/mL) = 973.9 mL = 0.9739 L
Molarity = moles / volume in litre = 2 moles / 0.9739 L = 2.05 M