Let Diameter=d, radius of sphere=rs=d/2New radius=d/2(1-25/100)=3d/8=rnCurved Surface Area=4πrs²=4π(d/2)²=πd²Curved Surface Area (when radius decreased)=4πrn²=4π(3d/8)²=9/16πd²Decrease=πd²-9/16πd²=7/16πd²