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Question:

The displacement of a particle executing simple harmonic motion is given by y = A₀ + Asinωt + Bcosωt. Then the amplitude of its oscillation is given by:

A² + B²

A₀ + √(A² + B²)

A₀² + (A + B)²

A + B

Solution:

Correct option is B. √(A² + B²)

Given, y = A₀ + Asinωt + Bcosωt
Equation of SHM
y' = y - A₀ = Asinωt + Bcosωt
Resultant amplitude, R = √(A² + B² + 2ABcos90°) = √(A² + B²)