The electron in a hydrogen atom first jumps from the third excited state to the second excited state and subsequently to the first excited state. The ratio of the respective wavelengths, λ₁/λ₂ of the photons emitted in this process is:<p></p>

The correct option is D

207

1/λ=R[(1/nf²)-(1/ni²)]

here for wavelength λ₁, nf=3, ni=4
1/λ₁=R(1/3² - 1/4²) = R(1/9 -1/16) = R(7/144)

for wavelength λ₂, nf=2, ni=3
1/λ₂=R(1/2² - 1/3²) = R(1/4 - 1/9) = R(5/36)

λ₁/λ₂ = (5/36)/(7/144) = (5/36) * (144/7) = 20/7 ≈ 207

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