Question:

The equation of a plane containing the line of intersection of the plane 2x-y-4=0 and y+2z-4=0 and passing through the point (1,1,0) is :

x+3y+z=4

x−y−z=0

2x−z=2

x−3y−2;z=−2;

Correct option is B. x−y−z=0
The required plane is (2x−y−4)+λ(y+2z−4)=0
it passes through (1,1,0) ⇒(2−1−4)+λ(1−4)=0⇒−3−3λ=0⇒λ=−1⇒x−y−z=0