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Question:

The equation of the plane containing the straight line x/2=y/3=z/4 and perpendicular to the plane containing the straight lines x/3=y/4=z/2 and x/4=y/2=z/3 is:

x+2y−z=0

x−y+z=0

3x+2y−z=0

5x+2y−z=0

Solution:

Plane 1:ax+by+cz=0contains linex2=y3=z4∴2a+3b+4c=0 ⋯ (i)Plane 2:a′x+b′y+c′z=0is perpendicular to plane containing lines.x3=y4=z2andx4=y2=z3∴3a′+4b′+2c′=0and4a′+2b′+3c′=0⇒a′12𕒸=b′8𕒽=c′6𕒵6⇒8a−b𕒵0c=0⋯(ii)From (i) and (ii), we geta󔼦+4=b32+20=c𕒶𕒶4⇒Equation of planex𕒶y+z=0