x+2y−z=0
x−y+z=0
3x+2y−z=0
5x+2y−z=0
Plane 1:ax+by+cz=0contains linex2=y3=z4∴2a+3b+4c=0 ⋯ (i)Plane 2:a′x+b′y+c′z=0is perpendicular to plane containing lines.x3=y4=z2andx4=y2=z3∴3a′+4b′+2c′=0and4a′+2b′+3c′=0⇒a′12=b′8=c′66⇒8a−b0c=0⋯(ii)From (i) and (ii), we geta+4=b32+20=c4⇒Equation of planexy+z=0